Class- 9th Subject - Mathematics Chapter -2
Class- 9th Subject - Mathematics Chapter -2 Exercise 2.2 1. Find the value of the polynomial (x)=5x−4x 2 +3 (i) x = 0 (ii) x = – 1 (iii) x = 2 Solution: Let f(x) = 5x−4x 2 +3 (i) When x = 0 f(0) = 5(0)-4(0) 2 +3 = 3 (ii) When x = -1 f(x) = 5x−4x 2 +3 f(−1) = 5(−1)−4(−1) 2 +3 = −5–4+3 = −6 (iii) When x = 2 f(x) = 5x−4x 2 +3 f(2) = 5(2)−4(2) 2 +3 = 10–16+3 = −3 2. Find p(0), p(1) and p(2) for each of the following polynomials: (i) p(y)=y 2 −y+1 Solution: p(y) = y 2 –y+1 ∴p(0) = (0) 2 −(0)+1=1 p(1) = (1) 2 –(1)+1=1 p(2) = (2) 2 –(2)+1=3 (ii) p(t)=2+t+2t 2 −t 3 Solution: p(t) = 2+t+2t 2 −t 3 ∴p(0) = 2+0+2(0) 2 –(0) 3 =2 p(1) = 2+1+2(1) 2 –(1) 3 =2+1+2–1=4 p(2) = 2+2+2(2) 2 –(2) 3 =2+2+8–8=4 (iii) p(x)=x 3 Solution: p(x) = x 3 ∴p(0) = (0) 3 = 0 p(1) = (1) 3 = 1 p(2) = (2) 3 = 8 (iv) P(x) = (x−1)(x+1) Solution: p(x) = (x–1)(x+1) ∴p(0) = (0–1)(0+1) = (−1)(1) = –1 p(1) = (1–1)(1+1) = 0(2) = 0 p(2) = (2–1)(2+1) = 1...